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x^2+720x=28800
We move all terms to the left:
x^2+720x-(28800)=0
a = 1; b = 720; c = -28800;
Δ = b2-4ac
Δ = 7202-4·1·(-28800)
Δ = 633600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{633600}=\sqrt{57600*11}=\sqrt{57600}*\sqrt{11}=240\sqrt{11}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(720)-240\sqrt{11}}{2*1}=\frac{-720-240\sqrt{11}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(720)+240\sqrt{11}}{2*1}=\frac{-720+240\sqrt{11}}{2} $
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